જો $P=\left[\begin{array}{ll}1 & 0 \\ 1 / 2 & 1\end{array}\right]$ તો $P^{50}$ મેળવો.
JEE MAIN 2021, Medium
Download our app for free and get started
$P=\left[\begin{array}{cc}1 & 0 \\ \frac{1}{2} & 1\end{array}\right]$
$P^{2}=\left[\begin{array}{ll}1 & 0 \\ \frac{1}{2} & 1\end{array}\right]\left[\begin{array}{ll}1 & 0 \\ \frac{1}{2} & 1\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]$
$P^{3}=\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]\left[\begin{array}{cc}1 & 0 \\ \frac{1}{2} & 1\end{array}\right]=\left[\begin{array}{cc}1 & 0 \\ \frac{3}{2} & 1\end{array}\right]$
$P^{4}=\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 2 & 1\end{array}\right]$
$\vdots$
$\therefore P^{50}=\left[\begin{array}{cc}1 & 0 \\ 25 & 1\end{array}\right]$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1ધારોકે $M=\left[\begin{array}{cc}0 & -\alpha \\ \alpha & 0\end{array}\right]$, જ્યાં $\alpha$ શુન્યેતર વાસ્તવિક સંખ્યા છે, અને $N=\sum_{k=1}^{49} M^{2 k}$.જો $\left(I-M^{2}\right) N=-2 I$ હોય તો $\alpha$ નું ધનપૂણાંક મૂલ્ય $\dots\dots$છે.View Solution
- 2શ્રેણિક $A = \left[ {\begin{array}{*{20}{c}}0&1&0\\1&0&0\\0&0&1\end{array}} \right]$ નો વ્યસ્ત મેળવો.View Solution
- 3If $1,\omega ,{\omega ^2}$ are the cube roots of unity, then $\Delta = \left| {\,\begin{array}{*{20}{c}}1&{{\omega ^n}}&{{\omega ^{2n}}}\\{{\omega ^n}}&{{\omega ^{2n}}}&1\\{{\omega ^{2n}}}&1&{{\omega ^n}}\end{array}\,} \right|$ is equal toView Solution
- 4શ્રેણિક $A = \left[ {\begin{array}{*{20}{c}} {{{10}^{30}} + 5}&{{{10}^{20}} + 4}&{{{10}^{20}} + 6}\\ {{{10}^4} + 2}&{{{10}^8} + 7}&{{{10}^{10}} + 2n}\\ {{{10}^4} + 8}&{{{10}^6} + 4}&{{{10}^{15}} + 9} \end{array}} \right]$ , $n \in N$, હોય તો $. .. $View Solution
- 5શ્રેણિક $f(x)=\left[\begin{array}{ccc}\cos x & -\sin x & 0 \\ \sin x & \cos x & 0 \\ 0 & 0 & 1\end{array}\right]$ ધ્યાને લો.View Solution
નીચે બે વિધાનો આપ્યા છે :
વિધાન $(I) :$ શ્રેણિક $f(x)$ નું વ્યસ્ત $f(-x)$ છે.
વિધાન $(II) :$ $f(x) f(y)=f(x+y)$
ઉપરના વિદ્યાનોના અનુસંધાને, નીચે આપેલ વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.
- 6જો સુરેખ સમીકરણ સંહતિ $x + ky + 3z = 0;3x + ky - 2z = 0$ ; $2x + 4y - 3z = 0$ ને શૂન્યતેર ઉકેલ $\left( {x,y,z} \right)$ હોય ,તો $\frac{{xz}}{{{y^2}}} = $. . . . .View Solution
- 7જો $a_i^2 + b_i^2 + c_i^2 = 1,\,\,(i = 1,2,3)$ અને ${a_i}{a_j} + {b_i}{b_j} + {c_i}{c_j} = 0$ $(i \ne j,i,j = 1,2,3)$ તો ${\left| {\,\begin{array}{*{20}{c}}{{a_1}}&{{a_2}}&{{a_3}}\\{{b_1}}&{{b_2}}&{{b_3}}\\{{c_1}}&{{c_2}}&{{c_3}}\end{array}\,} \right|^2} =.. . .$View Solution
- 8શ્રેણિક $A = \left[ {\begin{array}{*{20}{c}}{1/\sqrt 2 }&{1/\sqrt 2 }\\{ - 1/\sqrt 2 }&{ - 1/\sqrt 2 }\end{array}} \right]$ એ $. ..... . .$View Solution
- 9શ્રેણિકના વ્યસ્તનું અસ્તિત્વ હોય, તો તે શોધો : $\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & \cos a & \sin a \\ 0 & \sin a & -\cos a\end{array}\right]$View Solution
- 10$A,B,C$ અને $P,Q,R$ ની દરેક કિમંત માટે , $\left| {\,\begin{array}{*{20}{c}}{\cos (A - P)}&{\cos (A - Q)}&{\cos (A - R)}\\{\cos (B - P)}&{\cos (B - Q)}&{\cos (B - R)}\\{\cos (C - P)}&{\cos (C - Q)}&{\cos (C - R)}\end{array}\,} \right| =. . . $View Solution