b
\(\,\frac{{{{\left( {{t_{\frac{1}{2}}}} \right)}_1}}}{{{{\left( {{t_{\frac{1}{2}}}} \right)}_2}}}\,\, = \,{\left( {\frac{{{a_2}}}{{{a_1}}}} \right)^{n - 1}}\,\,\, \Rightarrow \,\,\frac{{{t_{\frac{1}{2}}}}}{{\frac{{{t_{\frac{1}{2}}}}}{2}}}\,\, = \,\,{\left( {\frac{{2a}}{a}} \right)^{n - 1}}\)

\(2\,\, = \,\,(2)\,{\,^{n - 1}}\,\,\,\,\,n\,\, - \,\,1\,\, = \,\,1\,\,\,\,\,\,\,\,\,n\,\, = \,\,2\)

તેથી , પ્રક્રિયાનો ક્રમ 2 થશે.