(નજીકના પૂર્ણાંકમાં રાઉન્ડ ઑફ) (ધારી લો : $\ln 10=2.303, \ln 2=0.693$)
\(C _{12} H _{22} O _{11}+ H _{2} O \frac{ I \text { order }}{ t _{1 / 2}=\frac{10}{3} hr } \underset{\text { Glucose }}{ C _{6} H _{12} O _{6}}+\underset{\text { Fructose }}{ C _{6} H _{12} O _{6}}\)
\(t =0 \quad\quad a =[ A ]_{0}\quad \quad \quad \quad -\quad \quad \quad \quad \quad -\)
\(t =9 hr \quad\quad a - x =[ A ]_{ t }\)
from \(I\) order kinetic : \(\frac{ k \times t }{2.303}=\log \frac{| A |_{0}}{| A |_{ t }}\)
\(\Rightarrow \frac{\ell n 2 \times 9}{\frac{10}{3} \times 2.303}=\log \left(\frac{1}{ f }\right)\)
\(\Rightarrow \frac{0.693 \times 9 \times 3}{23.03}=\log \left(\frac{1}{ f }\right)\)
\(\Rightarrow \log \left(\frac{1}{ f }\right)=0.81246=81.24 \times 10^{-2}\)
\(\Rightarrow x =81\)