જો $x = {\log _b}a,\,\,y = {\log _c}b,\,\,\,z = {\log _a}c$ તો $xyz = . . . .$
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b
(b) We have \(xyz = {\log _b}a \times {\log _c}b \times {\log _a}c\)
(b) We have \(xyz = {\log _b}a \times {\log _c}b \times {\log _a}c\)
\( = {{{{\log }_e}a} \over {{{\log }_e}b}} \times {{{{\log }_e}b} \over {{{\log }_e}c}} \times {{{{\log }_e}c} \over {{{\log }_e}a}} = 1\).
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