પ્રણાલી $A$ | પ્રણાલી $B$ |
સમોષ્મી પ્રણાલી | ડાયથર્મીક પાત્ર |
In case of Diathermic container, heat flow can occur to maintain the constant temperature.
$H - H$ બંધઊર્જા | $:\, 431.37 \,kJ\, mol^{-1}$ |
$C= C$ બંધઊર્જા | $:\, 606.10\, kJ \,mol^{-1}$ |
$C - C$ બંધઊર્જા | $:\, 336.49\, kJ\, mol^{-1}$ |
$C - H$ બંધઊર્જા | $:\, 410.50\, kJ\, mol^{-1}$ |
પ્રક્રિયા : $\begin{array}{*{20}{c}}
{H\,\,\,\,H} \\
{|\,\,\,\,\,\,\,\,|} \\
{C = C} \\
{|\,\,\,\,\,\,\,\,\,|} \\
{H\,\,\,\,H}
\end{array}\, + \,H - H\, \to \,\begin{array}{*{20}{c}}
{H\,\,\,\,H} \\
{|\,\,\,\,\,\,\,\,|} \\
{H - C - C - H} \\
{|\,\,\,\,\,\,\,\,\,|} \\
{H\,\,\,\,H}
\end{array}\,$
$3 HC \equiv CH _{( g )} \rightleftharpoons C _{6} H _{6(\ell)}$
[આપેલ : $\Delta_{f} G ^{\circ}( HC \equiv CH )=-2.04 \times 10^{5}\, J mol ^{-1}$
$\Delta_{f} G ^{\circ}\left( C _{6} H _{6}\right)=-1.24 \times 10^{5}\, J mol ^{-1} ; R =8.314\,\left. J K ^{-1} mol ^{-1}\right]$
$S{O_2} + \frac{1}{2}{O_2} \to S{O_3}$