\(\therefore \,{({\lambda _m})_1}{T_1} = {({\lambda _m})_2}{T_2}\,\,\,\therefore \,\,\,\,\frac{{{{({\lambda _m})}_1}}}{{{{({\lambda _m})}_2}}} = \frac{{{T_2}}}{{{T_1}}} = \frac{{0.26}}{{0.13}} = 2 \Rightarrow {T_2} = 2{T_1}\)

હવે સ્ટિફન - બૉલ્ટ્ઝમૅનના નિયમ મુજબ \(E \propto T^{4}\)

\(\therefore \,\frac{{{{\text{E}}_{\text{1}}}}}{{{{\text{E}}_{\text{2}}}}} = {\left( {\frac{{{T_1}}}{{{T_2}}}} \right)^4} = {\left( {\frac{1}{2}} \right)^4} = \frac{1}{{16}}\,\,\,\,\therefore \,\,\,{E_1}\,:\,{E_2} = 1:16\)