${\log _{10}}\frac{{{K_2}}}{{{K_1}}}\,\, = \,\,\frac{{Ea}}{{R\,\, \times \,\,2.303}}\,\left[ {\frac{{{T_2}\,\, - \,{T_1}}}{{{T_1}{T_2}}}} \right]$

આપેલ 

$\frac{{{K}_{2}}}{{{K}_{1}}}=3$, 

 $R=8.314J{{K}^{-1}}mo{{l}^{-1}},$

${{T}_{1}}=20+273=293\,K$, 

${{T}_{2}}=50+273=323\,K$

${{\log }_{10}}3=$ $\frac{Ea}{8.314\times 2.303}\left[ \frac{323-293}{323\times 293} \right]$

${{E}_{a}}=$ $\frac{2.303\times 8.314\times 323\times 293\times 0.477}{30}$ $=28811.8\,J\,mo{{l}^{-1}}$ $=28.8118\,KJ\,mo{{l}^{-1}}$