જયારે  $ T_2 = 37\,^oC$   $= 310\,K$,   $ k_2 = 2k$

સમીકરણમાં આ કિંમતોને મૂકતાં,

$\log \frac{{{k_2}}}{{{k_1}}}{\mkern 1mu} {\mkern 1mu}  = {\mkern 1mu} {\mkern 1mu} \frac{{{E_a}}}{{2.303R}}{\mkern 1mu} \left( {\frac{{{T_2}{\mkern 1mu}  - {\mkern 1mu} {T_1}}}{{{T_1}{T_2}}}} \right)$

$ \Rightarrow {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \log \frac{{2k}}{k}{\mkern 1mu} {\mkern 1mu}  = $ $\frac{E}{{2.303{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} 8.314}}{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} \frac{{310{\mkern 1mu} {\mkern 1mu}  - {\mkern 1mu} {\mkern 1mu} 300}}{{300{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} 310}}$

અથવા $\log \,{\mkern 1mu} 2{\mkern 1mu} {\mkern 1mu}  = {\mkern 1mu} {\mkern 1mu} \frac{{{E_a}}}{{2.303{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} 8.314}}{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} \frac{{10}}{{300{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} 310}}$

$ \Rightarrow $ અથવા $\log \,{\mkern 1mu} 2{\mkern 1mu} {\mkern 1mu}  = {\mkern 1mu} {\mkern 1mu} \frac{{{E_a}}}{{2.303{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} 8.314}}{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} \frac{{10}}{{300{\mkern 1mu} {\mkern 1mu}  \times {\mkern 1mu} {\mkern 1mu} 310}}$

ઉકેલતા મેળવવામાં આવતું 

${E_a}{\mkern 1mu} {\mkern 1mu}  = {\mkern 1mu} {\mkern 1mu} 53598.6\,J{\mkern 1mu} {\mkern 1mu} mo{l^{ - 1}}$

${\mkern 1mu}  = {\mkern 1mu} {\mkern 1mu} 53.6{\mkern 1mu} {\mkern 1mu} \,kJ{\mkern 1mu} \,{\mkern 1mu} mo{l^{ - 1}}$