$ = 50 - \frac{1}{2} \times 60 - \frac{3}{2} \times 40 $
$= 50 - 30 - 60 $
$= 50 - 90 = - 40\,J{K^{ - 1}}\,mol{e^{ - 1}}$
સંતુલને ${{\Delta G}} = {\text{0 - 20}} \times {\text{1}}{{\text{0}}^{\text{3}}} = T \times - 40$
$T = \frac{{20 \times 1000}}{{40}} = 500\,\,\,Kelvin$
$CO_{(g)} + \frac{1}{2} \,O_{2(g)}\rightarrow CO_{2(g)}$ અચળ તાપમાન અને દબાણ