\(ᴧ^{0} HOAC = ᴧ^{0} HCl + ᴧ^{0} NaOAC - ᴧ^{0} NaCl\)
\(= 426.2 + 91.0 - 226.5 = 290.7\)
આપેલ $: \frac{2.303 RT }{ F }=0.06 V$
$Pd _{( aq )}^{2+}+2 e ^{-} \rightleftharpoons Pd ( s ) \quad E ^{\circ}=0.83\,V$
$PdCl _4^{2-}( aq )+2 e ^{-} \rightleftharpoons Pd ( s )+4 Cl ^{-}( aq )$
$E ^{\circ}=0.65\,V$