For same conductivity cell, $G ^{*}$ is constant and hence $\kappa . R .=$ constant.
$\therefore 0.14 \times 4.19=\kappa \times 1.03$
or,$\kappa$ of HCl solution $=\frac{0.14 \times 4.19}{1.03}$
$=0.5695\, Sm ^{-1}$
$=56.95 \times 10^{-2} Sm ^{-1} \approx 57 \times 10^{-2} \,Sm ^{-1}$
(નજીકના પૂર્ણાંકમાં રાઉન્ડ ઑફ કરો) $[$ આપેલ $\left.: \frac{2.303 RT }{ F }=0.059\right]$
આપેલ: $E _{ x ^{2+} \mid x }^0=-2.36\,V$
$E _{ Y ^{3+} \mid Y }^0=+0.36\,V$
$\frac{2.303\,RT }{ F }=0.06\,V$
$\left[\right.$ આપેલ : $K _{ sp }( AgBr )=4.9 \times 10^{-13}$ at $298 K$
$\lambda_{ Ag ^{+}}^0=6 \times 10^{-3} Sm ^2\,mol ^{-1}$
$\lambda_{ Br ^{-}}^0=8 \times 10^{-3} Sm ^2\,mol ^{-1}$
$\left.\lambda_{ NO _3^{-}}^0=7 \times 10^{-3} Sm ^2\,mol ^{-1}\right]$