For same conductivity cell, $G ^{*}$ is constant and hence $\kappa . R .=$ constant.
$\therefore 0.14 \times 4.19=\kappa \times 1.03$
or,$\kappa$ of HCl solution $=\frac{0.14 \times 4.19}{1.03}$
$=0.5695\, Sm ^{-1}$
$=56.95 \times 10^{-2} Sm ^{-1} \approx 57 \times 10^{-2} \,Sm ^{-1}$
(નજીકનાં પૂર્ણાંકમાં રાઉન્ડ ઑફ). $\left[\right.$ આપેલ $, E_{C u^{2+} / C u}^{o}=0.34\, V , E _{ NO _{3}^{-} / NO_2 }^{\circ}=0.96\, V$ $,E _{ NO _{3} / NO _{2}}^{\circ}=0.79 \,V$ $\left.\frac{ RT }{ F }(2.303)=0.059\right]$
[આપેલ, $KCl$ નું મોલર દળ $74.5 \,g\, mol ^{-1}$ છે.]