Mass of solute $(KI) = 20\,g$
Mass of solvent $= 100-20 = 80\,g$
Molar mass of $KI = 38+128 = 166$
Molality $ = \frac{{gm\,(solute)}}{{mw\, \times Kg\,(solvent)}} = \frac{{20 \times 1000}}{{166 \times 80}} = 1.506 = 1.51$
$CaCO _{3( s )}+2 HCl _{( aq )} \rightarrow CaCl _{2( aq )}+ CO _{2( g )}+2 H _{2} O _{( l )}$
[બે દશાંશ બિંદુ સુધી ગણતરી કરો]