b
(b) In series combination of capacitors, voltage distributes on them, in the reverse ratio of their capacitance i.e. \(\frac{{{V_A}}}{{{V_B}}} = \frac{3}{2}\)\( ......(i)\)
Also \(V_A\) + \(V_B\) =\( 10 .......(ii)\)
On solving \( (i)\) and \((ii)\) \(V_A\) \(= 6V\), \(V_B = 4V\)