\([{t_{\frac{1}{2}}} = \frac{{0.693}}{{0.0433}} = \frac{{0.633}}{{2.25×\,\,{{10}^{ - 4}}}} = 3080\,\,] \) વર્ષ
$T$ (in, $K$) $- 769$ , $1/T$ (in, $K^{-1}$ ) $- 1.3\times 10^{-3},$
$\log_{10}K - 2.9\,T$ (in, $K$) $- 667$, $1/T$ (in, $K^{-1}) - 1.5\times 10^{-3}$, $\log_{10}\,K - 1.1$