\(v=\sqrt{\frac{N}{\mu}}\)
The tension \(N\) in the string varies as :
\(N=\pi \frac{M g}{L} \times x\) where \(x\) is length from the ground.
\(d t=\frac{d x}{v_x} \text { and } v_x=\sqrt{\frac{M g x}{L \times M / L}}=\sqrt{g x}\)
\(\int \limits_0^T d t=\int \limits_0^L \frac{d x}{\sqrt{g x}}\)
\(T=\int \limits_0^L 2 \sqrt{x} d x\)
\(T=\int \limits_0^L 2 \sqrt{L_g} \quad \dots (i)\)
If time to cover half length is \(T_2\).
\(T_2=\sqrt{2 L g}\) [By putting limits \(0\) to \(L / 2\) in equation \((i)\)]
\(\frac{T}{\sqrt{2}}=T_2\)
$y_1=5 \sin 2 \pi(75 t-0.25 x)$
$y_2=10 \sin 2 \pi(150 t-0.50 x)$
છે. આ બે તરંગોની તીવ્રતાનો ગુણોત્તર $\frac{I_1}{I_2}$ કેટલો છે.
(હવામાં ધ્વનિનો વેગ $330\;m/sec$ છે)