MCQ
${\left( {x - \frac{1}{x}} \right)^{18}}$ ના વિસ્તરણમાં મધ્યમપદ મેળવો.
- A$^{18}{C_9}$
- ✓${ - ^{18}}{C_9}$
- C$^{18}{C_0}$
- D${ - ^{18}}{C_{10}}$
$\therefore $Middle term is $10^{th}$ term.
==> ${T_{10}} = {}^{18}{C_9}{(x)^9}.\,{\left( { - \frac{1}{x}} \right)^9} = {\rm{ }} - {}^{18}{C_9}$.
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