MCQ
$\left| {\begin{array}{{}{c}}{ab}&1&{bc + ca}\\{bc}&1&{ca + ab}\\{ca}&1&{ab + bc}\end{array}} \right| = .........$
  • A
    $ab + bc + ca$
  • B
    $(a+b)(b+c)(c+a)$
  • C
    $2$
  • $0$

Answer

Correct option: D.
$0$
D

$\left| {\begin{array}{{}{c}}{ab}&1&{bc + ca}\\{bc}&1&{ca + ab}\\{ca}&1&{ab + bc}\end{array}} \right| = \left| {\begin{array}{{}{c}}{ab}&1&{ab + bc + ca}\\{bc}&1&{bc + ca + ab}\\{ca}&1&{ca + ab + b}\end{array}} \right|$ $(\because C_3\rightarrow C_3+C_1)$

$=(ab+bc+ca) \left| {\begin{array}{{}{c}}{ab}&1&1\\{bc}&1&1\\{ca}&1&1\end{array}} \right|$

$=0$ $(\because C_2=C_3)$

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