Question
Locate the image formed by refraction in the situation shown in figure.

Answer

$\mu_1=1, \ \mu_2=1.5,$

R = 20cm (Radius of curvature), u = -25cm

$\therefore \ \frac{\mu_2}{\text{v}}-\frac{\mu_1}{\text{u}}=\frac{\mu_2-\mu_1}{\text{R}}$

$\Rightarrow\frac{1.5}{\text{v}}=\frac{0.5}{20}-\frac{1}{25}=\frac{1}{40}-\frac{1}{25}=\frac{-3}{200}$

$\Rightarrow \ \text{v}=200\times0.5=-100\text{cm}.$

So, the image is 100cm from (P) the surface on the side of S.

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