de-Broglie wavelength, \(\lambda_{e}=\frac{h}{p}=\frac{h}{\sqrt{2 m E}}\)
For photon of energy, \(E=h v=\frac{h c}{\lambda_{p}}\)
\({\Rightarrow \lambda_{p}=\frac{h c}{E}}\)
\({\therefore \frac{\lambda_{e}}{\lambda_{p}}=\frac{h}{\sqrt{2 m E}} \times \frac{E}{h c}=\frac{1}{c}\left(\frac{E}{2 m}\right)^{1 / 2}}\)
(નાઇટ્રોજન અણુનું દળ :$4.64 \times 10^{-26}\, kg ,$
બોલ્ટ્ઝ્મેન અચળાંક : $1.38 \times 10^{-23}\, J / K ,$
પ્લાંક અચળાંક : $\left.6.63 \times 10^{-34}\, J . s \right)$
( ફોટોનની ઊર્જા $ = \frac{{1240}}{{\lambda {\rm{(in\, nm)}}}}\,eV$)