| List $I$ | List $II$ |
| $A$ Isothermal Process | $I$ Work done by the gas decreases internal energy |
| $B$ Adiabatic Process | $II$ No change in internal energy |
| $C$ Isochoric Process | $III$ The heat absorbed goes partly to increase internal energy and partly to do work |
| $D$ Isobaric Process | $IV$ No work is done on or by the gas |
Choose the correct answer from the options given below :
For isothermal process $T$ is constant
So $\Delta U =0$
$A \longrightarrow II$
Adiabatic process
$\Delta Q =0$
$\Delta Q =\Delta U +\Delta W$
$\quad \Delta U =-\Delta W$
Work done by gas is positive
So $\Delta U$ is negative
$B \longrightarrow I$
For Isochoric process $\Delta W =0$
$C \longrightarrow IV$
For Isobaric process
$\Delta W = P \Delta V \neq 0$
$\Delta U = nC _{ V } \Delta T \neq 0$
Heat absorbed goes partly to increase internal energy and partly do work.

