MCQ
$\mathop {\lim }\limits_{n \to \infty } {\left( {\frac{{\left( {n + 1} \right)\left( {n + 2} \right) \ldots .\;3n}}{{{n^{2n}}}}} \right)^{\frac{1}{n}}} = $
- A$\frac{9}{{{e^2}}}$
- B$3\log 3 - 2$
- C$\;\frac{{18}}{{{e^4}}}$
- ✓$\;\frac{{27}}{{{e^2}}}$