MCQ
$\mathop {\lim }\limits_{x \to 7} \frac{{2 - \sqrt {x - 3} }}{{{x^2} - 49}} = . . .$
- A$\frac{2}{9}$
- B$ - \frac{2}{{49}}$
- C$\frac{1}{{56}}$
- ✓$ - \frac{1}{{56}}$
$\mathop {\lim }\limits_{x \to 7} \frac{{2 - \sqrt {x - 3} }}{{{x^2} - 49}}$
$= \mathop {\lim }\limits_{x \to 7} \frac{{0 - \frac{1}{{2\sqrt {x - 3} }}}}{{2x}}$
$ = \mathop {\lim }\limits_{x \to 7} \frac{{ - 1}}{{4x\sqrt {x - 3} }} = \frac{{ - 1}}{{4.7\sqrt {7 - 3} }} = \frac{{ - 1}}{{56}}$.
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