$[O{H^ - }] = \frac{{10}}{{100}} \times 0.1 = 0.01;\,\,\,\,\,[{M^{ - 2}}] = \frac{{{K_{sp}}}}{{{{[O{H^ - }]}^2}}} = \frac{{{{10}^{ - 14}}}}{{{{[0.01]}^2}}} = {10^{ - 10}}$