Molecules of an ideal gas are known to have three translational degrees of freedom and two rotational degrees of freedom. The gas is maintained at a temperature of $T$. The total internal energy, $U$ of a mole of this gas, and the value of $\gamma\left(=\frac{ C _{ P }}{ C _{ v }}\right)$ given, respectively, by
A$U =\frac{5}{2} RT$ and $\gamma=\frac{6}{5}$
B$U =5 RT$ and $\gamma=\frac{7}{5}$
C$U =5 RT$ and $\gamma=\frac{6}{5}$
D$U =\frac{5}{2} RT$ and $\gamma=\frac{7}{5}$
JEE MAIN 2020, Medium
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D$U =\frac{5}{2} RT$ and $\gamma=\frac{7}{5}$
d Total degree of freedom $=3+2=5$
$U =\frac{ nfRT }{2} \Rightarrow \frac{5 RT }{2}$
$\gamma \Rightarrow \frac{ C _{ P }}{ C _{ V }} \Rightarrow 1+\frac{2}{ f } \Rightarrow 1+\frac{2}{5} \Rightarrow \frac{7}{5}$
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