$N _2$ અણુની આણ્વીય કક્ષકોની ઊર્જાઓનો સાચો ક્રમ શોધો :

Q: $N _2$ અણુની આણ્વીય કક્ષકોની ઊર્જાઓનો સાચો ક્રમ શોધો :

b For molecules like $B _2, C _2, N _2$ etc. the increasing order of energies of various molecular orbitals is $\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \sigma 2 p_{ z } < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma^* 2 p_{ z }$

Question

A$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma 2 p_{ z } < \sigma^* 2 p_{ z }$
B$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \sigma 2 p_{ z } < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma^* 2 p_{ z }$
C$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \sigma 2 p_{ z } < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma^* 2 p_{ z }$
D$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \sigma 2 p_{ z } < \sigma^* 2 p_{ z } < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right)$

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Solution

b
For molecules like $B _2, C _2, N _2$ etc. the increasing order of energies of various molecular orbitals is $\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \sigma 2 p_{ z } < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma^* 2 p_{ z }$

$Bond$	$E_{(diss)}(kJ(mol )^{(-1)})$
$C-A$	$240$
$C-B$	$328$
$C-C$	$276$
$C-D$	$485$

સ્તંભ $I$	સ્તંભ $II$
$(a)$ $XeF _{2}$	$(i)$ સમતલીય યોરસ
$(b)$ $XeF _{4}$	$(ii)$ રેખીય
$(c)$ $XeO _{3}$	$(iii)$ સમયોરસ પિરામિડલ
$(d)$ $XeOF_{4}$	$(iv)$ પિરામિડલ

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