$NO(g) \rightarrow \frac{1}{2} N_2(g)+ \frac{1}{2} O_2(g)$ સમાન તાપમાને શું થશે? :
\(N_{2}+O_{2} \rightarrow 2 N O\)
\(K=4 \times 10^{-4}\)
Hence for the reaction
\(N O \rightarrow \frac{1}{2} N_{2}+\frac{1}{2} O_{2}\)
\(K^{\prime}=\frac{1}{\sqrt{K}}\)
\(=\frac{1}{\sqrt{4 \times 10^{-4}}}\)
\(=50\)