At equilibrium, $1$ mole of $CO$ is present
Hence, $2-1=1$ moles of $CO$ has reacted.
$1$ mole of $CO$ will react with $1$ mole of $Cl_2$ to from $1$ mole of $COCl_2$.
$3-1=2$ moles of $Cl_2$ remains at equilibrium
The equlibrium constant
${K_c} = \frac{{[COC{l_2}]}}{{[CO][C{l_2}]}} = \frac{{\frac{{1\,mol}}{{5\,L}}}}{{\frac{{1\,mol}}{{5\,L}} \times \frac{{2\,mol}}{{5\,L}}}} = 2.5$
$2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
જો બંધ પાત્રમાં $0.1 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{NO}_{(\mathrm{g})}$ લેવામાં આવે તો, સંતુલન ૫૨ $\mathrm{NO}_{(\mathrm{g})}$ નો વિયોજન અંશ $(\alpha)$ શું થશે?
નીચેની પ્રક્રિયા માટે $K _{ C }$નું મૂલ્ય શું છે?
$NH_{3}(g) \rightleftharpoons \frac{1}{2} N _{2}(g)+\frac{3}{2} H_{2}(g)$
[આપેલ : $R=0.082 \,L \,atm\, K ^{-1}\, mol ^{-1}$ ]