At equilibrium, $1$ mole of $CO$ is present
Hence, $2-1=1$ moles of $CO$ has reacted.
$1$ mole of $CO$ will react with $1$ mole of $Cl_2$ to from $1$ mole of $COCl_2$.
$3-1=2$ moles of $Cl_2$ remains at equilibrium
The equlibrium constant
${K_c} = \frac{{[COC{l_2}]}}{{[CO][C{l_2}]}} = \frac{{\frac{{1\,mol}}{{5\,L}}}}{{\frac{{1\,mol}}{{5\,L}} \times \frac{{2\,mol}}{{5\,L}}}} = 2.5$
$\mathrm{PbCl}_{2(\mathrm{s})} \rightleftharpoons \mathrm{Pb}_{(\mathrm{ag})}^{2+}+2 \mathrm{Cl}_{(\mathrm{aq})}^{-}$
$300\; \mathrm{mL}\;\; 0.134 \;\mathrm{M} \;\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}$ અને $100\; \mathrm{mL}\;\; 0.4\; \mathrm{M}\; \mathrm{NaCl} ?$
ના મિશ્રણ માટે નીચેના પૈકી ક્યુ વિધાન સાયુ છે ?
$400\, K$ $\Delta G ^{\circ}=+25.2\, kJ mol ^{-1}$. એ $2 A ( g ) \rightleftharpoons A _{2}( g )$
આ પ્રકિયા માટે સંતુલન અચળાંક $K _{ C }$$...... \times 10^{-2}$
$\left.\log _{10} 2=0.30,1\, atm =1\, bar \right]$
$[$ antilog $(-0.3)=0.501]$