Question
  1. Name a compound that will be required to obtain butane using Kolbe's electrolytic method.
  2. Why does benzene show electrophilic substitution easily?
  3. Complete the following:

$\text{CH}_3-\text{C}=\text{CH}_2+\text{H}_2\text{O}\xrightarrow{\text{H}^+}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$

Answer

  1. CH3CH2COONa (sodium propanoate), on electrolysis will give butane.
  2. It is because benzene has $6\pi$ electrons, therefore, it attracts electrophile and undergo electrophilic substitution reactions.
  3. $\text{CH}_3-\text{C}=\text{CH}_2+\text{H}_2\text{O}\xrightarrow{\text{H}^+}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \ \ \ \ \ _{2-\text{Methyl propene}}\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \text{CH}_3-\text{C}-\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \ \ \ \ \ _{2-\text{Methyl propan-2-ol}}$

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