\(\Rightarrow x=1+\frac{x \times 1}{x+1}+1\)
\(\Rightarrow(x-2)=\frac{x}{x+1}\)
\(\Rightarrow x^2-x-2=x\)
\(\Rightarrow x^2-2 x-2=0\)
\(\text { So, } x=\frac{2 \pm \sqrt{12}}{2}\)
\(=1 \pm \sqrt{3}\,\Omega\)
neglecting negative value, \(x =1+\sqrt{3}\,\Omega\)