$A$. $\mathrm{Ti}^{3+}$ $B$. $\mathrm{Cr}^{2+}$ $C$. $\mathrm{Mn}^{2+}$ $D$.$\mathrm{Fe}^{2+}$ $E$. $\mathrm{Sc}^{3+}$
નીચે આપેલા વિકલ્પોમાંથી સૌથી બંધબેસતો જવાબ પસંદ કરો.
| lons | No. of unpaired electrons | Configuration |
| $ \mathrm{Ti}^{3+} $ | $1$ | $3 d^1$ |
| $ \mathrm{Cr}^{2+} $ | $4$ | $3 d^4$ |
| $ \mathrm{Mn}^{2+} $ | $5$ | $3 d^5$ |
| $ \mathrm{Fe}^{2+} $ | $4$ | $3 d^6$ |
| $ \mathrm{Sc}^{3+}$ | $0$ | $3 d^0$ |
Spin only magnetic moment is given by $\sqrt{n(n+2)} \mathrm{BM}$
$\therefore \mathrm{Cr}^{2+}$ and $\mathrm{Fe}^{2+}$ will have same spin only magnetic moment.
(પરમાણ્વીય ક્રમાંક ${Ho}=67$ )