Force per unit area = $\frac{{[ML{T^{ - 2}}]}}{{[{L^2}]}} = [M{L^{ - 1}}{T^{ - 2}}]$

Product of voltage and charge per unit volume $ = \frac{{V \times Q}}{{{\rm{Volume}}}} = \frac{{VIt}}{{{\rm{Volume}}}} = \frac{{{\rm{Power}} \times {\rm{Time}}}}{{{\rm{Volume}}}}$

$ \Rightarrow $ $\frac{{[M{L^2}{T^{ - 3}}]\,[T]}}{{[{L^3}]}} = [M{L^{ - 1}}{T^{ - 2}}]$

Angular momentum per unit mass = $\frac{{[M{L^2}{T^{ - 1}}]}}{{[M]}} = [{L^2}{T^{ - 1}}]$

So angular momentum per unit mass has different dimension.