$A \,|\, A^+\, (xM)\, ||\, B^+ \,(yM)\, |\, B$
જો માપેલા $emf + + 0.20\, V$ હોય, તો કોષપ્રક્રિયા ...........
\(A\left|A^{+}(x M)\right|\left|B^{+}(y M)\right| B\)
The EMF of cell is \(+0.20\) V. So, cell reaction is
possible. The half-cell reactions are given as follows
(i) At negative pole
\(A \rightarrow A^{+}+e^{-} \quad \text { (oxidation) }\)
(ii) At positive pole
\(B^{+}+e^{-} \rightarrow B \quad \text { (reduction) }\)
Hence, cell reaction is
\(A+B^{+} \rightarrow A^{+}+B, E_{c e l l}^{0}=+0.20 V\)
$V^{2+}(aq) + 2e^{-} \rightarrow V$, $E^o = -1.19\,V; $
$Fe^{3+}(aq) + 3e^{-} \rightarrow Fe$, $E^o = -0.04\,V:$
$Au^{3+}(aq) + 3e^{-} \rightarrow Au$, $E^o = + 1.40\,V;$
$Hg^{2+}(aq) + 2e^{-} \rightarrow Hg$, $E^o = + 0.86\,V$
જલીય દ્રાવણમાં $NO^-_{3}$ દ્રારા કયા ધાતુઓના યુગ્મનું ઓક્સિડેશન નથી થતુ?
(નજીકનાં પૂર્ણાંકમાં રાઉન્ડ ઑફ). $\left[\right.$ આપેલ $, E_{C u^{2+} / C u}^{o}=0.34\, V , E _{ NO _{3}^{-} / NO_2 }^{\circ}=0.96\, V$ $,E _{ NO _{3} / NO _{2}}^{\circ}=0.79 \,V$ $\left.\frac{ RT }{ F }(2.303)=0.059\right]$
$(i)$ $Zn| Zn^{2+} {(1\,M)}|| Cu^{2+}{(0.1\,M)}| Cu$
$(ii)$ $Zn| Zn^{2+} {(1\,M)}|| Cu^{2+}(1\,M) |Cu $
$(iii)$ $Zn| Zn^{2+} {(0.1\,M)}|| Cu^{2+}{(1\,M)}| Cu$