$Pt | H_2\,(g) | H^{+}_{(aq)} (10^{-8}\, M) | | H^{+}_{(aq)} (0.001\,M) | H_2\,(g) | Pt$
\(E_{cell} = \,\,0.0591\,\,\log \,\,\frac{{{C_2}}}{{{C_1}}}\)
\( = \,\,0.0591\,\,\log \,\,\frac{{{{10}^{ - 3}}}}{{{{10}^{ - 8}}}}\,\, = \,\,0.0591\,\,\log \,\,{10^5}\)
\( = \,\,0.0591\,\, \times \,5\, = \,\,0.2955\,volt\)
$mol^{-1}, ᴧ^{0}\, KCl = 150\, S\, cm^{2}\, mol^{-1}$ હોય, તો $ᴧ^{0}\, NaBr$ .............. ${\rm{S}}\,{\rm{c}}{{\rm{m}}^2}{\rm{mo}}{{\rm{l}}^{ - 1}}$ શોધો.
$\Lambda _{C{H_3}COONa}^o =91.0\, S \,cm^2 /equiv.$
$\Lambda _{HCl}^o =426.2 \,S \,cm^2 /equiv.$
તો એસિટીક એસિડના જલીય દ્રાવણ ${\Lambda ^o}$ ગણવા કઈ વધારાની માહિતી/જથ્થો જોઈએ ?
$Fe_{(aq)}^{3 + } + {e^ - } \to Fe_{(aq)}^{2 + }$ ; ${E^o} = 0.771{\mkern 1mu} \,volts;{\mkern 1mu} $
${\mkern 1mu} {I_{2(g)}} + 2{e^ - } \to 2I_{(aq)}^ - \,;{\mkern 1mu} $ ${E^o} = 0.536{\mkern 1mu} \,volts$
કોષ પક્રિયા $2Fe^{3+}_{(aq)} + 2l^{-}_{(aq)} \rightarrow 2Fe^{2+}_{(aq)} + I_{2(g)}$ માટે $E^o_{cell} = ….$