Ground state of electronic configuration \(X e=[K r] 4 d^{10} 5 s^2 5 p^6\)

Excited state of electronic configuration \(Xe =[ Kr ] 4 d ^{10} 5 s ^2 5 p ^3 5 d ^3\)

The electronic configuration of oxygen \(=1 s^2 2 s^2 2 p^4\)

In \(XeO _3\), the hybridisation of \(Xe\) is \(sp ^3\), It form \(3\) \(\sigma\) bond and three \(\pi\) bonds with three oxygen atoms and contain one lone pair of electron.

The oxygen atom form bond with \(Xe\) like \(s p^3+p_x, s p^3+p_y, s p^3+p_z\), but never form \(s p^3+s\)