Here $O.N.$ of $N$ increases from $O$ in ${N_2}$ to $+2 $ in $NO, 2- $ and that of decreased from $O$ in ${O_2}$ to $-2 $ in $O,$ therefore, it is a redox reaction.
$S{O_2}\, + \,\,2{H_2}S\,\,\, \to \,\,3S\,\, + \,\,2{H_2}O$
$4Fe + 3{O_2}\, \to \,4F{e^{3 + }} + 6{O^{2 - }}$
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