b
The compound \(XeO_3\) is an uncommon hydrolysis product betwen \(XeF_2\) and \(XeF_4\).

\((i)\)  \(\mathrm{XeF}_{2}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{Xe}+\frac{1}{2} \mathrm{O}_{2}+2 \mathrm{HF}\)

\((ii)\)  \(3 \mathrm{XeF}_{4}+6 \mathrm{H}_{2} \mathrm{O}\rightarrow \mathrm{XeO}_{3}+2 \mathrm{Xe}+\frac{3}{2} \mathrm{O}_{2}+12 \mathrm{HF}\)