$(i) \,\,\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH - C{H_3}} \\
{\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}\,\xrightarrow{{{H^ + }/heat}}\,\,\mathop A\limits_{[Major\,product]} \, + \,\mathop B\limits_{[Minor\,product]} $
$(ii)\,\, A\xrightarrow[{in\,\,absence\,\,\,of\,peroxide}]{{HBr,\,dark}}\,\,\mathop C\limits_{[Major\,product]} \, + \,\mathop D\limits_{[Minor\,product]} $
મુખ્ય નીપજ $(A)$ અને $(C)$ અનુક્રમે શું હશે ?
$\underset{\begin{smallmatrix}
(A) \\
Major
\end{smallmatrix}}{\mathop{\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C=CH-C{{H}_{3}} \\
\end{matrix}}}\,$ $\xrightarrow[{in\,\,absence\,\,of\,\,peroxide}]{{HBr\,,\,dark}}$ $\mathop {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,}
\end{array}\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - C{H_2} - C{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}}\limits_{(C)\,\,\,major} $ $\mathop {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - CH - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}}\limits_{(D)\,\,\,minor} $
સંયોજનો $A$ અને $B$ અનુક્રમે શોધો.
કથન $A :$ $Image-I$ ને $Zn \cdot Hg / HCl$ નો ઉપયોગ કરીનો $Image-II$ માં સરળતા થી રિડકશન કરી શકાય છે.
કારણ $R :$ $Zn - Hg / Hcl$ નો ઉપયોગ કાર્બોનિલ સમૂહનો $- CH _2$ - સમૂહ માં રિડકશન કરવામાં થાય છે.
ઉપરના વિધાનોના સંદર્ભમાં નીચે આપેલા વિકલ્પોમાંથી સાયો જવાબ પસંદ કરો.
$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}CHC{H_2}C{H_2}N{H_2}}
\end{array}$ $\xrightarrow[{triethyla\min e}]{{ethyl\,formate\,\left( {1\,equiv} \right)}}$

$I. \,\,C{H_2} = CHC{H_2}Cl$
$II.\,\,C{H_3}C{H_2}C{H_2}Br$
$III.\,\,{(C{H_3})_3}CC{H_2}Br$
$IV.\,\,C{H_3}C{H_2}C{H_2}Cl$


