d
Generally as the size of the atom increases, bond dissociation energy decreases, so in halogens \(I_2\) have lowest bond dissociation energy, but the bond dissociation energy of chlorine is higher than that of fluorine because in fluorine there is a greater

repulsion between non-bonding electrons \((2 \mathrm{p})\)

Hence, the order of bond dissociation energy is

\(C I_{2} < F_{2} < B r_{2} < I_{2}\)

respective Bond dissociation energy \((kJ/mol)\;=\;243,159,193,151\)