In $\left[N i\left(P P h_{3}\right)_{2} C l_{2}\right]$ both the ilgands $P P h^{3}$ and $C 1$ are weak and as such cannot pair up the d-electrons. Thus hybridisation is $s p^{3}$ and shape is tetrahedral.
[પરમાણુ ક્રમાંક : $Zn = 30, Sc = 21, $$Ti = 22, Cr = 24$]
$(i)\, Pt(SCN)_2 · 3PEt_3$
$(ii)\, CoBr · SO_4 · 5NH_3$
$(iii)\, FeCl_3 · 6H_2O$