${K_h} = \frac{{{K_w}}}{{{K_a} \times {K_b}}}$
$log K_h - log K_w - log K_a - log K_b$
$- log Kh = -log Kw + log Ka + log Kb$
$pK_h = pK_w - pK_a - pK_b$
$pK_h = 14 + logK_a - pK_b $
(for $AgCl$ માટે $K_{sp}$ $= 1.8 \times 10^{-10},$ for $PbCl_2$ માટે $ K_{sp}$ $= 1.7 \times 10^{-5}$)