જો \(M\) અચળ હોય તો \({v_{rms}}\, \propto \,\sqrt T \,\,\,\,\,\therefore \,\,\,\frac{{v{'_{rms}}}}{{{v_{rms}}}} = \,\sqrt {\frac{{T'}}{T}} \,\,\,v{'_{rms}}\,\, = \,\,\,\,2{v_{rms}}\,\,\, \Rightarrow \,\,\frac{{2v{'_{rms}}}}{{{v_{rms}}}}\, = \,\,\sqrt {\frac{{T'}}{T}} \,\,\,\,\therefore \,\,\,\,T'\,\, = \,\,4T\)

હવે ચાર્લ્સ નાં નિયમ અનુસાર \( V  \propto  T   \Rightarrow \,\,\,\frac{{V'}}{V} = \frac{{T'}}{T}\,\,\,\,\,\,\therefore \,\,\frac{{V'}}{V} = \frac{{4T}}{T}\,\,\,\,\therefore \,\,\,V'\, = \,4V\)