Therefore, horizontal range \((R)=0.4 \mathrm{~m}\)
\(\mathrm{R}=\mathrm{u} . \mathrm{t}\)
Similarly, in vertical direction
\( \mathrm{h}=\frac{1}{2} \mathrm{gt}^2 \)
\( 0.4=\frac{1}{2} \mathrm{gt}^2 \)
\( 0.4=\frac{1}{2} \mathrm{~g}\left(\frac{0.4}{\mathrm{u}}\right)^2 \)
\( \mathrm{u}^2=2 \)
\( \mathrm{u}=\sqrt{2} \mathrm{~m} / \mathrm{s}\)
Therefore, \(\mathrm{x}=2\)
$\left[ g =10 m / s ^{2} \text { }\right]$લો