\({I_c}\,\, = \,\,\frac{{100}}{{95}}\,\, \times \,\,{I_c}\,\, = \,\,\frac{{100}}{{95}}\,\, \times \,\,10mA\,\, = \,\,10.53\,\,mA\,\,\,\left( {\,\because \,\,{I_c}\,\, = \,\,10\,mA} \right)\)
હવે, \(I_e = I_c + I_b \) \(I_b = I_e - I_c = 10.53 - 10 = 0.53 mA\)
$A\,\, 0\,\, 0\,\, 1\,\, 1$
$B\,\, 0\,\, 1\,\, 0\,\, 1$
$Y \,\,1\,\, 0\,\, 0\,\, 1$