MCQ
Number of atoms in $11.2\, L$ of $CO_2$ at $NTP$ is .............. $N_A$
  • $1.5$
  • B
    $0.5$
  • C
    $3$
  • D
    $\frac{2}{3} $

Answer

Correct option: A.
$1.5$
a
$\mathrm{n}=\frac{11.2}{22.4}=\frac{1}{2}$

No. of molecules of $\mathrm{CO}_{2}=\frac{1}{2} \times \mathrm{N}_{\mathrm{A}}$

No. of atoms $=3 \times \frac{1}{2} \times \mathrm{N}_{\mathrm{A}}=1.5 \mathrm{N}_{\mathrm{A}}$

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