MCQ
Number of atoms in $11.2\, L$ of $CO_2$ at $NTP$ is .............. $N_A$
- ✓$1.5$
- B$0.5$
- C$3$
- D$\frac{2}{3} $
No. of molecules of $\mathrm{CO}_{2}=\frac{1}{2} \times \mathrm{N}_{\mathrm{A}}$
No. of atoms $=3 \times \frac{1}{2} \times \mathrm{N}_{\mathrm{A}}=1.5 \mathrm{N}_{\mathrm{A}}$
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