On the superposition of two harmonic oscillations represented by ${x_1} = a\,\sin \,\left( {\omega t + {\phi _1}} \right)$ and ${x_2} = a\,\sin \,\left( {\omega t + {\phi _2}} \right)$ a resulting oscillation with the same time period and amplitude is obtained. The value of ${\phi _1} - {\phi _2}$ is .... $^o$
A$120$
B$90$
C$60$
D$15$
Medium
Download our app for free and get started
A$120$
a Resultant amplitude $=\sqrt{a_{1}^{2}+a_{2}^{2}+2 a_{1} a_{2} \cos \Delta \phi}$
$\Rightarrow \phi_{1}-\phi_{2}=120^{\circ}$ or $\frac{2 \pi}{3} \mathrm{rad}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A simple pendulum is hanging from a peg inserted in a vertical wall. Its bob is stretched in horizontal position from the wall and is left free to move. The bob hits on the wall the coefficient of restitution is $\frac{2}{{\sqrt 5 }}$. After how many collisions the amplitude of vibration will become less than $60°$
A man measures the period of a simple pendulum inside a stationary lift and finds it to be $T$ sec. If the lift accelerates upwards with an acceleration $\frac{g}{4}$, then the period of the pendulum will be
A steady force of $120\ N$ is required to push a boat of mass $700\ kg$ through water at a constant speed of $1\ m/s$ . If the boat is fastened by a spring and held at $2\ m$ from the equilibrium position by a force of $450\ N$ , find the angular frequency of damped $SHM$ ..... $rad/s$
lfa simple pendulum has significant amplitude (up to a factor of $1/e$ of original) only in the period between $t = 0\ s$ to $t = \tau \ s$, then $\tau$ may be called the average life of the pendulum. When the spherical bob of the pendulum suffers a retardation ( due to viscous drag) proportional to its velocity with $b$ as the constant of proportionality, the average life time of the pendulum is (assuming damping is small) in seconds
An object of mass $0.2\ kg$ executes simple harmonic along $X-$ axis with frequency of $\frac{{25}}{\pi } Hz$ . At the position $x$ = $0.04\ m$ , the object has kinetic energy of $0.5\ J$ and potential energy of $0.4\ J$ amplitude of oscillation in meter is equal to
A particle is executing simple harmonic motion with a time period $T.$ At time $t = 0$, it is at its position of equilibrium. The kinetic energy-time graph of the particle will look like
A particle executes simple harmonic motion and is located at $x = a, b$ and $c$ at times $t_0, 2t_0$ and $3t_0$ respectively. The frequency of the oscillation is
A force of $6.4\ N$ stretches a vertical spring by $0.1\ m$. The mass that must be suspended from the spring so that it oscillates with a time period of $\pi/4\ second$ is .... $kg$