MCQ
One and a half mole of oxygen combine with aluminium to form $Al_2O_3$ , then the weight of aluminium metal used in this reaction is ............. $\mathrm{gms}$ (Atomic weight of $Al = 27$ )
- A$27$
- B$81$
- C$108$
- ✓$54$
✓
Answer
Correct option: D.
$54$
d
$3$ moles of oxygen react with $108$ $g$ of $Al$
$3$ moles of oxygen react with $108$ $g$ of $Al$
$1$ moles of oxygen react with $108 / 3\, g$ of $Al$
And $0.5$ mole of oxygen react with $108 \times 0.5/ 3\, g$ of $Al$
$\mathrm{Al}=18$ $gram$
$1$ moles of oxygen react with $108 / 3\, g$ of $Al$
And $1$ mole of oxygen react with $108 \times 1/ 3\, g$ of $Al$
$\mathrm{Al}=36$ $gram$
$=18+36$
$54\,gm$
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