One end of a uniform wire of length $L$ and of weight $W$ is attached rigidly to a point in the roof and a weight ${W_1}$ is suspended from its lower end. If $S$ is the area of cross-section of the wire, the stress in the wire at a height $3L/4$ from its lower end is
IIT 1992, Medium
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(c) Total force at height $3L/4$ from its lower end
$=$ Weight suspended $+$ Weight of $3/4$ of the chain
$ = {W_1} + (3W/4)$
Hence stress $ = \frac{{{W_1} + (3W/4)}}{S}$
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