The interatomic distance for a metal is $3 \times {10^{ - 10}}\,m$. If the interatomic force constant is $3.6 \times {10^{ - 9}}\,N/{{\buildrel _{\circ} \over {\mathrm{A}}}}$, then the Young's modulus in $N/{m^2}$ will be
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(a) $Y = \frac{{3.6 \times {{10}^{ - 9}}N/\mathop A\limits^o }}{{3 \times {{10}^{ - 10}}m}}$$ = 1.2 \times {10^{11}}N/{m^2}$
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