Let temperature be $T_{o}$

$State \,2$

since $1-2$ is isochoric process $\frac{P}{T}=$ Constant Thus Temperature $=4 T_{o}$

$State\, 3$

since $3-1$ is an isobaric process $\frac{V}{T}=$Constant Thus Temperature $=4 T_{o}$

The average molecular speed is directly proportional to $\sqrt{\frac{R T}{M}}$ $\Rightarrow v \propto \sqrt{T}$

Hence

State $1 \quad v \propto T_{o}$

State $\quad 2 \quad v \propto \sqrt{4 T_{o}}=2 \sqrt{T_{o}}$

State $3 \quad v \propto \sqrt{4 T_{o}}=2 \sqrt{T_{o}}$

$\Rightarrow$ Ratio $=1: 2: 2$