d
Pressure is defined as normal force per unit area.
Force is calculated as change in $ momentum/time.$
By this answer is $2 \mathrm{N} / \mathrm{m}^{2}$
None of the option matches so this question must be Bonus.
Detailed solution is as following:
$Magnitude\, of\, change\, in\, momentum \,per\, collision$ $=2$ $mv$
Pressure $=\frac{\text { Force }}{\text { Area }}=\frac{N(2 m v)}{1}$
${=\frac{10^{22} \times 2 \times 10^{-26} \times 10^{4}}{1}} $
${=2 \mathrm{N} / \mathrm{m}^{2}}$
